Let See How Amazing is Mathematics (1=2)

[Bas_tum_Pak]

we have to prove that 2=1

Let start

Let a=1 and b=1

so a=b

a*a=ab

a*a-b*b=ab-b*b

(a+b)(a-b)=b(a-b)

after cancelling (a-b) on both sides

(a+b)=b

(1+1)=1​

2=1

hence proved.
​

 

[sonofakila]

^^^
(a+b)(a-b)=b(a-b) Incorrect

cant multiply by 0

 

[Bas_tum_Pak]

^^^
(a+b)(a-b)=b(a-b) Incorrect

cant multiply by 0

I think you are weak in Maths, or Forget about Formula :

a*a - b*b = (a+b)(a-b)

Check ..

 

[rajeev]

I think you are weak in Maths, or Forget about Formula :

a*a - b*b = (a+b)(a-b)

Check ..

What he is saying is correct.

(a+b)(a-b)=b(a-b)
If a=b at this stage, then it is
(1 +1) * 0 = 1 * 0

which is 0 =0.

You cannot divide 0 or both sides by cancelling (a-b).

 

[Bas_tum_Pak]

What he is saying is correct.

(a+b)(a-b)=b(a-b)
If a=b at this stage, then it is
(1 +1) * 0 = 1 * 0

which is 0 =0.

You cannot divide 0 or both sides by cancelling (a-b).

I am Not Saying any thing ,
My each Step is Right,
Why you putting Values at the middle ?
I proved (a+b)=b Thats Matter ..

 

[sonofakila]

^^^
why do you mean by putting values in the middle?
if you do not sustitute given values for a and b how do you get

a*a=ab
you cant multiply/divide '0' to a non zero number in equality/inequality in math.

so while
a*a-b*b=ab-b*b =>(a+b)(a-b)=b(a-b)

(a+b) * (a-b) != b * (a-b) (since a=b and a !=0 and b !=0)

 

[xebex]

I am Not Saying any thing ,
My each Step is Right,
Why you putting Values at the middle ?
I proved (a+b)=b Thats Matter ..

WRONG. First of all, U CAN NOT EQUATE TWO DIFFERENT NUMBERS WITHOUT THE PRESENCE OF A VARIABLE.PERIOD

What u basically saying is

Let a=1 and b=1

so 1=1

1*1=1*1

1-1=1-1

0=0(derivation stops right here. bcoz it prooves the fact that a=b)

Since u have given the value at the begining to a and b then u r responsible to stop deriving it right at where it becomes Zero.

ie, (a+b)(a-b)=b(a-b)
(a+b)x0=bx0
0=0

Now, if i were to give u an equation a^2-b^2=ab-b^2 without giving any values to a and b then u can solve like (a+b)=b. ie, a=0. which means what ever u add to 0 gives the number u added.

Now if i set the condition a=1, b=1 and give u to solve the same quation,a^2-b^2=ab-b^2, then u will endup with

0=0

In otherwards, u have to make a proper question for us to solve if there is something to solve (in this case nothing). But i respect ur curiosity.

 

[Bas_tum_Pak]

^^^
why do you mean by putting values in the middle?
if you do not sustitute given values for a and b how do you get

a*a=ab
you cant multiply/divide '0' to a non zero number in equality/inequality in math.

so while
a*a-b*b=ab-b*b =>(a+b)(a-b)=b(a-b)

(a+b) * (a-b) != b * (a-b) (since a=b and a !=0 and b !=0)

You are negating what you have said before .

if a=1 & b=1

so as you stated above
(1+1)*(1-1)=1*(1-1)
0=0

so why (a+b) * (a-b) != b * (a-b) ?

 

[Bas_tum_Pak]

WRONG. First of all, U CAN NOT EQUATE TWO DIFFERENT NUMBERS WITHOUT THE PRESENCE OF A VARIABLE.PERIOD

What u basically saying is

Let a=1 and b=1

so 1=1

1*1=1*1

1-1=1-1

0=0(derivation stops right here. bcoz it prooves the fact that a=b)

Since u have given the value at the begining to a and b then u r responsible to stop deriving it right at where it becomes Zero.

ie, (a+b)(a-b)=b(a-b)
(a+b)x0=bx0
0=0

Now, if i were to give u an equation a^2-b^2=ab-b^2 without giving any values to a and b then u can solve like (a+b)=b. U could use it like a general equation.

Now if i set the condition a=1, b=1 and give u to solve the same quation,a^2-b^2=ab-b^2, then u will endup with

0=0

In otherwards, u have to make a proper question for us to solve if there is something to solve (in this case nothing). But i respect ur curiosity.

Yes Your point is good,
When I stated it i knew it, Here concept is wrong but way of showing was Right.

 

[sonofakila]

self deleted

 

[Bas_tum_Pak]

What about This Beauty Maths :

1 x 8 + 1 = 9
12 x 8 + 2 = 98
123 x 8 + 3 = 987
1234 x 8 + 4 = 9876
12345 x 8 + 5 = 98765
123456 x 8 + 6 = 987654
1234567 x 8 + 7 = 9876543
12345678 x 8 + 8 = 98765432
123456789 x 8 + 9 = 987654321

1 x 9 + 2 = 11
12 x 9 + 3 = 111
123 x 9 + 4 = 1111
1234 x 9 + 5 = 11111
12345 x 9 + 6 = 111111
123456 x 9 + 7 = 1111111
1234567 x 9 + 8 = 11111111
12345678 x 9 + 9 = 111111111
123456789 x 9 +10= 1111111111

9 x 9 + 7 = 88
98 x 9 + 6 = 888
987 x 9 + 5 = 8888
9876 x 9 + 4 = 88888
98765 x 9 + 3 = 888888
987654 x 9 + 2 = 8888888
9876543 x 9 + 1 = 88888888
98765432 x 9 + 0 = 888888888​

And look at this symmetry:

1 x 1 = 1
11 x 11 = 121
111 x 111 = 12321
1111 x 1111 = 1234321
11111 x 11111 = 123454321
111111 x 111111 = 12345654321
1111111 x 1111111 = 1234567654321
11111111 x 11111111 = 123456787654321
111111111 x 111111111 = 12345678987654321
​

 

[BlackenTheSky]

Solve by factorization

9x(sqr)-6x-8=0 |9*8=72

=9x(sqr) -12x-6x-8=0

=3x(3x-4)-2(3x-4)=0

= (3x-4) (3x-2) proved

 

[Barrett]

can anyone explain the significance of number '13'

 

[MastanKhan]

Hi,

Jaques de Molay was executed on the 13th.

 

[Barrett]

Hi,

Jaques de Molay was executed on the 13th.

hey,

Can you please provide a link because all the links suggest that he was tried in a court on the 18th and then taken to an island on the Siene and burned

Even if he was executed on the 13th, what is the significance of the number in religions.

Thanks.