Can you solve the world's hardest logic puzzle?

[45'22']

I guess Yes or No will ignore a question based on invalid premises while Random will give an answer. So you'll know who Random is within two questions and can then proceed as I've indicated.

Easier to do it if you have an "apple", maybe.

Consider the first 2 God's are true and false God's and u have to present the 3rd question to the random god....then how will u know which one is true and which one is false....

U r logic is gud but it's not enuff to give a 100 percent correct answer...
ur logic depends upon who answers the question first
If random comes up in 1st or 2nd attempt then voila otherwise back to square one

 

[Solomon2]

Let's see, if Yes and No are true divinities....the first two questions will be to the same god and will be if the fellow on the left/right will ALWAYS say ja or da when asked if the apple is red. If both answers are the same you're dealing with No or Random. If not you're dealing with Yes.

Then you ask another god about whether the other two would ALWAYS give the same answers when asked. No must answer - oops, out of time here, gotta go. It's been fun!

Consider the first 2 God's are true and false God's -

By asking the right two questions of the same god you've already figured out who Random is so you don't ask Random any or any more questions.

 

[45'22']

Let's see, if Yes and No are true divinities....the first two questions will be to the same god and will be if the fellow on the left/right will ALWAYS say ja or da when asked if the apple is red. If both answers are the same you're dealing with No or Random. If not you're dealing with Yes.

Then you ask another god about whether the other two would ALWAYS give the same answers when asked. No must answer - oops, out of time here, gotta go. It's been fun!

What's true divinities????

Answer me simply the 3 questions u gonna ask to the 3 God's

 

[Solomon2]

What's true divinities????

Answer me simply the 3 questions u gonna ask to the 3 God's

You can't know that ahead of time because it depends on answers you get from previous gods. Really, I've made it as simple as I can. Perhaps a better communicator could do better.

 

[45'22']

You can't know that ahead of time because it depends on answers you get from previous gods. Really, I've made it as simple as I can. Perhaps a better communicator could do better.

I think u r changing d criteria
D question states


"Three gods A, B, and C are called, in some order, True, False, and Random. True always speaks truly, False always speaks falsely, but whether Random speaks truly or falsely is a completely random matter. Your task is to determine the identities of A, B, and C by asking three yes-no questions; each question must be put to exactly one god. The gods understand English, but will answer all questions in their own language in which the words for 'yes' and 'no' are 'da' and 'ja', in some order. You do not know which word means which."

Source: Can you solve the world's hardest logic puzzle?

Do u agree that we have to ask each god only 1 question???

 

[Solomon2]

Do u agree that we have to ask each god only 1 question???

No. Each question must be put to exactly one god. The condition is that you can't ask two or three gods the same question (and you can't ask more than one god a question each time.)

 

[45'22']

No. Each question must be put to exactly one god. The condition is that you can't ask two or three gods the same question (and you can't ask more than one god a question each time.)

So we can ask infinite number of question to any god as long as it is not same as the questions we r asking to the other God's

 

[Aepsilons]

You don't know who is truth....

To quote Pontius Pilate, "What is truth?"

Gloria excelsis empiricus!

It's that strange time of year, the lull between Christmas and New Year, when you're not reallycelebrating but not really working either. So, how about you wrap your brain around the world's hardest logic puzzle to keep yourself amused? Y'know, just for fun.

New Scientist has a lovely feature (which is available to read if you sign up for a free account) in its Christmas issue about the world's most difficult logic problem. If you're wondering what could possibly be so tough, check it out:

"Three gods A, B, and C are called, in some order, True, False, and Random. True always speaks truly, False always speaks falsely, but whether Random speaks truly or falsely is a completely random matter. Your task is to determine the identities of A, B, and C by asking three yes-no questions; each question must be put to exactly one god. The gods understand English, but will answer all questions in their own language in which the words for 'yes' and 'no' are 'da' and 'ja', in some order. You do not know which word means which."

It was dreamt up—and solved—by US logician George Boolos shortly before his death in 1996. What makes it so difficult is it's incredible amount of problems, all squeezed into one puzzle: language barriers, untruthfulness, and randomness, too. Philosophers claims that cracking the puzzle reveals the true nature of logic itself to those willing to toil with the problem—but if you can't be bothered, you can find a (relatively) simple solution here.

(sorry, the link to the solution isn't working properly. I'll post a working link below)
https://dl.dropboxusercontent.com/u/4458028/sshlpe.pdf

Logic games ! Are we studying for the LCATs or something? lol

 

[SvenSvensonov]

Logic games ! Are we studying for the LCATs or something? lol

Ha, ha, no just trying to provide some mental exercise to those that are willing to give it the time. PDF seems devoid of intelligence sometimes, I wanted to help.

 

[Solomon2]

So we can ask infinite number of question to any god as long as it is not same as the questions we r asking to the other God's

Carefully pick three out of an infinite number of questions.

 

[45'22']

Carefully pick three out of an infinite number of questions.

Okay I got it now...


What you r saying is
We have 3 questions....
we can put them to either 1 each or even 3 questions to only 1 god.....
the condition being no same question can be asked...

So what u r doing is asking a hypothetical question to 1st god then 2nd god....
the god if true or false won't be able to answer this so by the end of ur 2nd question u will know who is the random god.....
and then u r left it with 1 question...
and you r presenting it to either the true god or the false god with a definite answer...
their answer will reveal their identity...
so...if Random comes up in first or second attempt,u get to ask a question to each of the gods
Otherwise if the random god is the 3rd god then we r either asking 2 questions to true god and 1 to false or 2 to false God's and 1 to true
And skipping a question to the random god
Is this the way u solved it????

 

[SamDNguyen]

Poor boy ask : Are you going to say "Ja" for yes, only if you know that I am currently rich?

A: False God will always answer, "Ja"
B: True God will not answer "..."
C: Random God will answer randomly, either "da" or "ja". If he answer "da" then he is random.

 

[Developereo]

I thought the world's hardest puzzle was to figure out what exactly is Will Ferrel's talent supposed to be!

 

[The SC]

Not 9 answers but only 3

You need to ask only 1 question to each god...
After ur 3 questions,u have 3 answers in the following order
Ja ja da
Ja da ja
Da ja ja

Based on this you should decide which God among a,b,c is true,false,random...


Not. That easy dude

If you ask the question, are you the truth guy? in the first, scond and third lines, you'll see a pattern which is a diagonal, meaning he is 3rd in the first line, 2nd in the 2nd line and first in the 3rd line.
Now if you ask the question, are you the lies guy? in the same way for the three lines, he can be 1 or 2, in the second line he can be 1 or 3, and in the third line he can be 2 or 3.
The third question should ask the random guy, are you some random guy? then he can be in the same order or reverse order of the lies guy.
So, we get :the answers for the questions in order of 1 to 3:

Da ja da
or
Da da da

Ja da da
or
Ja ja da

and
Ja ja da
or
Da da ja

Now it should be easier to solve...I'll come back to it when i'll have time.

 

[Mercenary]

Man I couldn't even understand the answer.