Can you solve the world's hardest logic puzzle?

[The SC]

It says in some order. I will quote the original puzzle for clarification:

If you take it as random, with 3 questions, then it should give 9 answers from where you can deduce the 3 identities, but the possibilities are more,so one should find out all the possibilities before deciding which 3 questions will yield the most probable idendities...needs some calculations,not very high mathematics but mostly logic.

 

[45'22']

I can give 1 identity but not all 3
The randomness of the puzzle is too high
Will try this on weekend :p
Bookmarked

 

[45'22']

If you take it as random, with 3 questions, then it should give 9 answers from where you can deduce the 3 identities, but the possibilities are more,so one should find out all the possibilities before deciding which 3 questions will yield the most probable idendities...needs some calculations,not very high mathematics but mostly logic.

Not 9 answers but only 3

You need to ask only 1 question to each god...
After ur 3 questions,u have 3 answers in the following order
Ja ja da
Ja da ja
Da ja ja

Based on this you should decide which God among a,b,c is true,false,random...


Not. That easy dude

 

[Kloitra]

If you take it as random, with 3 questions, then it should give 9 answers from where you can deduce the 3 identities, but the possibilities are more,so one should find out all the possibilities before deciding which 3 questions will yield the most probable idendities...needs some calculations,not very high mathematics but mostly logic.

This is why it is called hardest logic puzzle!
Solution is available on wiki, but I will attempt before seeing it.

 

[Solomon2]

Not 9 answers but only 3

You need to ask only 1 question to each god...
After ur 3 questions,u have 3 answers in the following order
Ja ja da
Ja da ja
Da ja ja

Based on this you should decide which God among a,b,c is true,false,random...


Not. That easy dude

No, you can ask more than one question of the same god. It's very tricky but the idea is to take advantage of the gods qualities/weaknesses, that they are ALWAYS infallible and can ONLY answer questions with Yes, No, or Random.

Do it right and two of the gods won't be able to give an answer (and therefore blow up!) and thus you'll know by the question asked and the god remaining who each god is (or was).

 

[45'22']

No, you can ask more than one question of the same god. It's very tricky but the idea is to take advantage of the gods qualities/weaknesses, that they are ALWAYS infallible and can ONLY answer questions with Yes, No, or Random.

Do it right and two of the gods won't be able to give an answer (and therefore blow up!) and thus you'll know by the question asked and the god remaining who each god is (or was).

Have u solved it???

 

[zip]

Leave out da ja...can any one give me answer with yes/no ?

 

[unbiasedopinion]

I dont know who is who but after reading that white paper my head is about to explode.

 

[Solomon2]

Have u solved it???

I think so. The way the problem is stated doesn't mean you can't ask the same god more than one question but that you can't ask the same question of two different gods.

The easiest bit is to discover which god is Random. This can be done without solving the language issue because the other two will blow up if asked what Random would say ("Would that guy on your left/right say my apple is red?") since they cannot give a definite answer. If after two questions the god hasn't blown up then you know you are dealing with Random.

The second and third questions (if needed) must be asked of another god in a way that allows you to discover which god is Yes or No. Ask what Random (if third question) said about when the other unknown guy was asked about the apple. No will have to give a different answer than Random whereas Yes will have to repeat the same.

If it's the second question ask the non-Random god a question and for the third question ask the SAME god what his previous answer was. Yes will have to repeat his words while No will have to say something different.

There you go, you've identified all three gods. (You still won't know the identities of ja and da but that's not what you're trying to determine in the problem statement.)

Don't be too impressed. I read the paper first. This is the easiest solution I could distill from it.

I think at most only one god blows up in my solution.

 

[zip]

I think so. The way the problem is stated doesn't mean you can't ask the same god more than one question but that you can't ask the same question of two different gods.

The easiest bit is to discover which god is Random. This can be done without solving the language issue because the other two will blow up if asked what Random would say ("Would that guy on your left/right say my apple is red?") since they cannot give a definite answer. If after two questions the god hasn't blown up then you know you are dealing with Random.

The second and third questions (if needed) must be asked of another god in a way that allows you to discover which god is Yes or No. Ask what Random (if third question) said about when the other unknown guy was asked about the apple. No will have to give a different answer than Random whereas Yes will have to repeat the same.

If it's the second question ask the non-Random god a question and for the third question ask the SAME god what his previous answer was. Yes will have to repeat his words while No will have to say something different.

There you go, you've identified all three gods. (You still won't know the identities of ja and da but that's not what you're trying to determine in the problem statement.)

Don't be too impressed. I read the paper first. This is the easiest solution I could distill from it.

I think at most only one god blows up in my solution.

Very impressive
You will exhaust two questions to determine who is random god right ? Then how will you determine others with single question left ?

 

[Solomon2]

Very impressive
You will exhaust two questions to determine who is random god right ? Then how will you determine others with single question left ?

If three questions are needed to discover who Random is then you ask one of the others to confirm that the first god you questioned answered a question with ja or da. You already know that answer so Yes will have to repeat the answer while No will have to say something different. (Alternatively you could lie to them and thus Yes will give a different answer and No will repeat but you'll still know which is which, as long as you're keeping track of who said what.)

 

[zip]

If three questions are needed to discover who Random is then you ask one of the others to confirm that the first god you questioned answered a question with ja or da. You already know that answer so Yes will have to repeat the answer while No will have to say something different. (Alternatively you could lie to them and thus Yes will give a different answer and No will repeat but you'll still know which is which, as long as you're keeping track of who said what.)

Two questions are enough to single out random god but only single question is left out of three no ? Or am l wrong somewhere ?

 

[Solomon2]

More difficult would be if the gods were true divinities - if Yes and No can actually divine what Random will/would say. Then they don't blow up. (That's a questionable given since apparently that robs Random of free will but hey, that's the same objection Einstein had to quantum mechanics.) Then you have to formulate questions differently. I haven't worked that out yet.

Two questions are enough to single out random god but only single question is left out of three no ? Or am l wrong somewhere ?

One or two questions are enough to discover who Random is. You ask one of the remaining gods about a previous answer. No will contradict while Yes will agree.

 

[zip]

How about asking question
Is it from last week you started to lie ?

 

[Solomon2]

How about asking question
Is it from last week you started to lie ?

I guess Yes or No will ignore a question based on invalid premises while Random will give an answer. So you'll know who Random is within two questions and can then proceed as I've indicated.

Easier to do it if you have an "apple", maybe.