Can you solve the world's hardest logic puzzle?

[Solomon2]

Okay I got it now...


What you r saying is
We have 3 questions....
we can put them to either 1 each or even 3 questions to only 1 god.....
the condition being no same question can be asked...

So what u r doing is asking a hypothetical question to 1st god then 2nd god....
the god if true or false won't be able to answer this so by the end of ur 2nd question u will know who is the random god.....
and then u r left it with 1 question...
and you r presenting it to either the true god or the false god with a definite answer...
their answer will reveal their identity...
so...if Random comes up in first or second attempt,u get to ask a question to each of the gods
Otherwise if the random god is the 3rd god then we r either asking 2 questions to true god and 1 to false or 2 to false God's and 1 to true
And skipping a question to the random god
Is this the way u solved it????

Yes, you've got it.

The thing is, what if the Yes & No gods are true divinities - if they can divine ahead of time what Random will say - then they won't blow up when asked a question about Random, Yes/No will simply echo or mirror what Random's response would/will be when asked about his response. Then it becomes more complicated.

To solve this variant I would ask god #1 a question with an indeterminate answer:

"What is zero divided by zero?"

God #1 will either ignore it or blow up if he is Yes or No while Random will give an answer.

If #1 is Random then you only need determine between Yes or No as previously described, by asking #2 about #1's answer.

If #1 is silent or blows up you need to determine which of the survivors is Random and which is Yes or No. Can you figure out how to do that?