Let See How Amazing is Mathematics (1=2)

[Skeptic]

wrong

Arre Meri 94 Rotis Ka kya hua. No comments.

Am I on your ignore list??

 

[FlyingEagle]

Arre Meri 94 Rotis Ka kya hua. No comments.

Am I on your ignore list??

kindly divide it. 94 is wrong

suppose it take 94 roti then
94-1(1 to the dog)=93
ist friend part is 93/3 =31
Remaining roti's = 93-31 =62

2nd friend = 62 -1 (1 to the dog)=61
2nd friend part = 61/3 = 20.33333

Wrong we cannot go in decimals

 

[Comet]

sorry I think its 79

79 = 26 +26 +26 +1 (first friend ate)
52 = 17 + 17 + 17 +1 (second friend ate)
34 = 11 + 11 + 11 + 1 (third friend ate)
22 = 7 + 7 + 7 + 1 ( all ate)

 

[Skeptic]

kindly divide it.

Kara To Tha:

31+31+31+1
10+10+10+1
3+3+3+1
1+1+1

 

[FlyingEagle]

Kara To Tha:

31+31+31+1
10+10+10+1
3+3+3+1
1+1+1

wrong.

if first one ate 31 roti and give 1 to the dog then 94-32= 64 otis left. how u can divide it by 10+10+10+1

 

[Creder]

Dear God....only indians and pakistanis can go this crazy over math...8 pages and counting

 

[FlyingEagle]

Kara To Tha:

31+31+31+1
10+10+10+1
3+3+3+1
1+1+1

some other number greater than 94.........come on calculate it

 

[AliFarooq]

8+8+8+1
5+5+5+1
3 + 3 +3 +1
2+2+2

total rotis = 25

 

[Iggy]

Not matter how many they eat ,they are satisfied na..thats all i wanna know

 

[FlyingEagle]

8+8+8+1
5+5+5+1
3 + 3 +3 +1
2+2+2

total rotis = 25

good going increase it. Akhir ma dog ka hisa kaha gaya

 

[AliFarooq]

good going increase it. Akhir ma dog ka hisa kaha gaya

so does dog eats equal rotis in end or 1?

 

[Bushy]

I may be wrong but what I think is if the rotis are not to be broken, then how can one of them eats exactly one third (his part) and spares one more for the dog, and the next one finds it easy to divide the next bunch of rotis in exactly three parts (since next bunch of rotis wouldn't be divisible by 3)? Either the first one cannot divide it in three equal parts to eat his portion and spare +1 for the dog, or if he can, then the second one cannot.

They all cannot keep dividing that bunch of rotis in 3 equal parts, while sparing exactly 1 more for the dog.

Please correct me if I am wrong, I am very keen on checking out the solution to this problem lol

 

[FlyingEagle]

so does dog eats equal rotis in end or 1?

yES IN THE SAME SEQUENSE. eQUAL PART TO THE FRIENDS AND 1 TO THE DOG

 

[FlyingEagle]

I may be wrong but what I think is if the rotis are not to be broken, then how can one of them eats exactly one third (his part) and spares one more for the dog, and the next one finds it easy to divide the next bunch of rotis in exactly three parts (since next bunch of rotis wouldn't be divisible by 3)? Either the first one cannot divide it in three equal parts to eat his portion and spare +1 for the dog, or if he can, then the second one cannot.

They all cannot keep dividing that bunch of rotis in 3 equal parts, while sparing exactly 1 more for the dog.

Please correct me if I am wrong, I am very keen on checking out the solution to this problem lol

Every one divide the roti's into 3 equal part and seperate 1 for the dog. This [COLOR="Red[B]"]"How Amazing is Mathematics[/B]"[/COLOR]

 

[Iggy]

Can i get an answer before i log out???On behalf of the all the members here "WE SURRENDER " now tell us the answer