Let See How Amazing is Mathematics (1=2)

[Bushy]

Well the exact answer is "79". Umaip answered it but I equested him to wait for someother members. Good Going.................

Todays question is very easy:

A cow gives 5 kg milk, A buffallo gives 3 kg milk and a goat gives 1/4 kg milk. Collect 19 kg of milk from maximum 7 animals.

Kindly explain the number of cows, buffalos and goats?
Note: They shouldn't be more than 7 in total?

Thanks for the answer FlyingEagle, that was a good one

Bahot bezti ho gayi, now I won't answer any based on guesses lol

 

[FlyingEagle]

I'm also looking for its solution
I hope all of us will find its solution.

 

[AliFarooq]

4 cows, but from the last cow only take 4 litters lol:

 

[Bushy]

I'm also looking for its solution
I hope all of us will find its solution.

Is it compulsory to milk all the animals?

 

[AliFarooq]

2 cows + 3 Bufflaos

10 + 9 = 19

 

[Skeptic]

Well the exact answer is "79". Umaip answered it but I equested him to wait for someother members. Good Going.................

Nope, The questions mentions they all divided rotis equally. So the share of DOG must be equal to the 3 guys (Not Possible) or dog gets no rotis at all (My Answer).

 

[Zee-Gen]

Well my friend umair I used more logic than math…....!!!!

This technique, put all the values in excel

http://img200.imageshack.us/i/71123449.png/

=G12-1 equal to First minus 1 for God (note: G12 is a column where 79 is written)

=G15/3*2 equal to Remaining when 2nd person wake up

=G15-G17 equal to 1st person consume

=G17-1 equal to Second minus 1 for dog

=G19/3*2 equal to Remaining when 3rd person wake up

=G19-G21 equal to 2nd person consume

=G21-1 equal to Third minus 1 for dog

=G23/3*2 equal to When all wake up

=G23-G25 equal to 3rd person consume

=G25-1 equal to Fourth minus 1 for dog

=G27/3 equal to No decimal

Now all u have to do is to change the values in G12 like 50, 51, 52……until u get “no decimal” answer

 

[Comet]

Well my friend umair I used more logic than math…....!!!!

This technique, put all the values in excel

http://img200.imageshack.us/i/71123449.png/

=G12-1 equal to First minus 1 for God (note: G12 is a column where 79 is written)

=G15/3*2 equal to Remaining when 2nd person wake up

=G15-G17 equal to 1st person consume

=G17-1 equal to Second minus 1 for dog

=G19/3*2 equal to Remaining when 3rd person wake up

=G19-G21 equal to 2nd person consume

=G21-1 equal to Third minus 1 for dog

=G23/3*2 equal to When all wake up

=G23-G25 equal to 3rd person consume

=G25-1 equal to Fourth minus 1 for dog

=G27/3 equal to No decimal

Now all u have to do is to change the values in G12 like 50, 51, 52……until u get “no decimal” answer

I did this on Paper:
x = y + y + y + 1 ( one y for first friend and 1 for Dog)
2y = z + z + z + 1( one Z for 2nd friend and 1 for Dog)
2z = u + u + u + 1( one u for 3rd friend and 1 for Dog)
2u = v + v + v + 1( one v for each friend and 1 for Dog)

now put values for u so that 2z is divisible by 3
I put different values and end up putting 7 that yeilded
2u = 7+7+7+1 = 22
u = 11
2z = 11+11+11+1 = 34
z = 17
2y = 17+17+17+1 = 52
y = 26
x = 26+26+26+1 = 79

 

[FlyingEagle]

Is it compulsory to milk all the animals?

Yes the milk will be collected from all the animals at least 4m one.

 

[Zee-Gen]

FlyingEagle r u sure about all the animals???……because all we have to use 4 goats in order to get 1 kg milk or a non-decimal number……now 18 kg and 3 animals left and its impossible to get 18 kg milk with this combination…….means the now question is like:

Buffalo = 3 kg
Cow = 5 kg

We cannot use 3 animals to get 18 kg……its impossible even from cow…...!!!

 

[FlyingEagle]

FlyingEagle r u sure about all the animals???……because all we have to use 4 goats in order to get 1 kg milk or a non-decimal number……now 18 kg and 3 animals left and its impossible to get 18 kg milk with this combination…….means the now question is like:

Buffalo = 3 kg
Cow = 5 kg

We cannot use 3 animals to get 18 kg……its impossible even from cow…...!!!

Yes I confirmed it twice from my uncle (Who ask this from me). We have to collect from all the animals. I'm also looking for its solution.

 

[Iggy]

Yes I confirmed it twice from my uncle (Who ask this from me). We have to collect from all the animals. I'm also looking for its solution.

2 cows and 3 buffaloes.. lets make kabab with those goats

 

[makikirkiri]

Yes I confirmed it twice from my uncle (Who ask this from me). We have to collect from all the animals. I'm also looking for its solution.

there is only only and only 1 solution to this :
2 cows and 3 bufalloes.
If we must collect from all animals ,then since cows and bufalloes give integral number of kgs of milk,the milk collected from goats must also be an integral quantity.Since number of animals <=7,the only possible number of goats that can be milked is 4 giving 1kg of milk.rest 18 kgs must be collected from 3 animal at the max, which is not possible.The max we can collect from 3 animals is 15 kgs fom 3 cows.
so...no sol is possible if all the animals must be used

 

[Bas_tum_Pak]

Yes, I just Disturbed by doing these calculations

, It is Impossible to include Goats.
Let see what FlyingEagle bringing for us tomorrow.

 

[Comet]

bufalloes give milk?