What's new

Calculus Help *Please participate in this thread

Hey Guys - Please help
Can you guys tell me
If -1 < y-5 < 1

technically it don't make sense unless you know the value of Y..

-1 < y-5 < 1

in other words y-5 is greater than -1 and less than 1

so that mean y-5= 0

y=5

so if you put y=5 in all these equations

1) 4 < y <6
2) -6 < y < -4
3) y > 4
4 ) y < 6
5) 0 <y-4<2
6) 2 < y/2 <3
7) 1/6 < 1/y < 1/4
8) (y-5) < 1

then they are all true except no 2
 
this is algebra. :P

for the problem, only 2nd is false.
 
Hey Guys - Please help
Can you guys tell me
If -1 < y-5 < 1 which of the following statements about y are true and which are not true?
1) 4 < y <6
2) -6 < y < -4
3) y > 4
4 ) y < 6
5) 0 <y-4<2
6) 2 < y/2 <3
7) 1/6 < 1/y < 1/4
8) mod(y-5) < 1

Also please explain how you guys determine whether the statement is true or not - i mean how do i solve this on my own ?explain the concept please..I hope you guys can help as this a lot of members on this forum are engineers and this just a simple Cal-1 question.

All correct

This is not calculus{ a simple inequality} we used to do these things in 10th standard
 
1,3, 4, 5,6,7 are true all others all false :)

fro the equation -1<y-5<1 means that y is must be great than 4 and less than 6 so its values can varies from 4.0000001 to 5.999999

and 8 also. thanks
 
1,3, 4, 5,6,7 are true all others all false :)

fro the equation -1<y-5<1 means that y is must be great than 4 and less than 6 so its values can varies from 4.0000001 to 5.999999

and 8 also. thanks

Dude its simple y-5 is greater than -1 and less than 1 so its between -1 and 1 which is 0
y-5=0
y=5

its so simple
 
Thank so much guys - Just one more question please help
1) Integrate the given function of the given surface
Parabolic Cylinder G(x,y,z) = x, over the parabolic cylinder y = x^2, 0 <=x <= 2, 0 <= z <= 3
 
Thank so much guys - Just one more question please help
1) Integrate the given function of the given surface
Parabolic Cylinder G(x,y,z) = x, over the parabolic cylinder y = x^2, 0 <=x <= 2, 0 <= z <= 3

This is an elementary multiple integral problem. I think you should spend some time on a problem instead of posting and waiting for a response. A good Calculus book I suggest is Calculus, Early transcendentals by Anton, Bivens and Davies.
 
Back
Top Bottom