500
BANNED

- Joined
- Aug 18, 2010
- Messages
- 16,675
- Reaction score
- 38
- Country
- Location
For sake of simplicity I neglect gravity and drag forces. This is a formula of rockets final speed:
I = specific impulse or exhaust gasses velocity, M - total rocket mass, M(t) - final rocket mass, Mp - mass of the propellant. Since typical exhaust gasses velocity is about 3000 m/s, we get this simplified formula:
All we need to know for our calculations is total mass of rocket (M) and mass of propellant (Mp).
Now lets take Falcon 9 rocket as example. It has two stages. Here approximate weights:
425 t - total 1st stage
400 t - propellant in 1st stage
1 t - interstage adapter (connects 1st and 2nd stages)
94 t - total 2nd stage
90 t - propellant in 2nd stage
8 t - payload with fairing
Total weight: 425+1+94+8= 528 t
Lets calculate its final speed.
1st stage: V = 3000*ln(528/528-400) = 3000*ln(528/128) = 4251 m/s
Total second stage with payload is 94+8=102 t. So here its speed contribution:
2nd stage V = 3000*ln(102/102-90) = 3000*ln(102/12)= 6420 m/s
Together they provide 4251 + 6420 = 10,671 m/s
===========================================
Now lets calculate same total mass of propellant rocket but single state.
Two stages combined have 400+90= 490 t of propellant. Since we dont need the interstate adapter and second stage engine we save up to 2 tons of weight.
So we get 526 t total mass including 490 t of propellant.
And here its speed:
V = 3000*ln(526/526-490) = 3000*ln(526/36) = 8045 m/s
================================================
Despite saving mass on interstage and second stage engine we lose more than 2,600 m/s of speed with same mass of propellant. Thats huge.
But there is more. Lets assume we still insist on 1 stage rocket, just make it bigger to increase speed. Lets increase propellant weight 2 times!
We get 1044 t total mass rocket (with same 8 t payload) and 980 t of propellant.
V = 3000*ln(1044/1044-980) = 3000*ln(1044/64) = 8376 m/s
We increased propellant weight twice, but speed increased only by 300 m/s. More than 2000 m/s less than 2 stage rocket with half of the propellant!
I = specific impulse or exhaust gasses velocity, M - total rocket mass, M(t) - final rocket mass, Mp - mass of the propellant. Since typical exhaust gasses velocity is about 3000 m/s, we get this simplified formula:
All we need to know for our calculations is total mass of rocket (M) and mass of propellant (Mp).
Now lets take Falcon 9 rocket as example. It has two stages. Here approximate weights:
425 t - total 1st stage
400 t - propellant in 1st stage
1 t - interstage adapter (connects 1st and 2nd stages)
94 t - total 2nd stage
90 t - propellant in 2nd stage
8 t - payload with fairing
Total weight: 425+1+94+8= 528 t
Lets calculate its final speed.
1st stage: V = 3000*ln(528/528-400) = 3000*ln(528/128) = 4251 m/s
Total second stage with payload is 94+8=102 t. So here its speed contribution:
2nd stage V = 3000*ln(102/102-90) = 3000*ln(102/12)= 6420 m/s
Together they provide 4251 + 6420 = 10,671 m/s
===========================================
Now lets calculate same total mass of propellant rocket but single state.
Two stages combined have 400+90= 490 t of propellant. Since we dont need the interstate adapter and second stage engine we save up to 2 tons of weight.
So we get 526 t total mass including 490 t of propellant.
And here its speed:
V = 3000*ln(526/526-490) = 3000*ln(526/36) = 8045 m/s
================================================
Despite saving mass on interstage and second stage engine we lose more than 2,600 m/s of speed with same mass of propellant. Thats huge.
But there is more. Lets assume we still insist on 1 stage rocket, just make it bigger to increase speed. Lets increase propellant weight 2 times!
We get 1044 t total mass rocket (with same 8 t payload) and 980 t of propellant.
V = 3000*ln(1044/1044-980) = 3000*ln(1044/64) = 8376 m/s
We increased propellant weight twice, but speed increased only by 300 m/s. More than 2000 m/s less than 2 stage rocket with half of the propellant!