Correct me if I'm wrong but the difference in G at low and high altitudes (attainable by aircraft) is negligible. For example, the SR-71's (one of the highest flying aircraft ever) highest attainable altitude was 25,929m or 25.929Km. The average distance at the equator from the Earth's centre of gravity is 6400Km with an average G of 9.8m/sec^2.
So the SR-71 flying at 25,929m would experience,
g1/g2 = (r1/r2)^2
9.8/g2 = (6425.929/6400)^2
g2 = 9.7210724123056078770968667923652 m/sec^2 acceleration due to gravity.
which when rounded off is 0.9919462G (a difference of 0.80538% only). You can actually get this variation in G on the surface of the Earth as well.
Higher altitudes in flight are more desired due to the difference in atmospheric density. The video, I believe, is on the effects of low 'relative gs'. These would, of course, differ in multiples of 0.80538% of x when at 25,929m (x being the relative g experienced by the aircraft at the time) but it still would be negligible, e.g. a turn which induces 9gs near the surface of the Earth would still induce 8.9275158gs at 25,929m. Plus none of the aircraft seem to be making sharp changes in their vector.