Chemistry Help?

[East or West India Best]

Can you help me because the answer in the book is different from what I have:

S+ 3/2O2--> SO3 ∆H= -395.2kJ
2SO2 + O2 --> 2SO3 ∆H=-198.2kJ

Calculate ∆H for S+ O2 --> SO2

I did [products] - [reactants] and I got 494.3kJ but the book says it's -296.1kJ.

Where am I going wrong?

 

[Shamain]

Abbay aik to tera nick zehar lagta hai mujhay.
Aur book ko choro woh sab jhoot hota hai.


Ok i will solve for you.

Firstly, reverse equation two, then minus 198.4 will become positive.
Then take equation one and mulitply whole by 2, that way heat absorbed will become -790(2*395.4).

Then add both the equations ,final answer will be.
Equation.
2S+2O2------->2SO2....... delta -592.4
Divide whoe equation by 2 and you get

S+O2----->SO2 delta -296.2kJ .
@east or west india not besT.

Shamain from Pangistan. ¯\_(ツ)_/¯